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All 3 posts Subject: Stoichiometry Help (BDO->GBL) Please login to post Down

ShaiGuy
(Stranger)
09-20-03 07:57
No 460079
      Stoichiometry Help (BDO->GBL)

In the solvent free oxidation of BDO to GBL a 50% potassium permanganate and 50% 20/80 mixture of copper sulphate pentahydrate and alumina are added to BDO at a ratio of 2 mmmol BDO to ~4g oxidant. I'm not sure what the mechanism of this reaction looks like, so I was wondering if anyone could help me figure out a more precise ratio of BDO:oxidant, as I'm not all that confident with "~4g".
Many Thanks,
ShaiGuy

Rhodium
(Chief Bee)
09-20-03 13:23
No 460097
User Picture       Stoichiometry

Maybe the authors of the article wasn't perfectly sure about the mechanism either, and therefore were unable to supply a more precise amount. They may simply have found out by trial and error that this amount gave the best result.

ShaiGuy
(Stranger)
09-20-03 16:40
No 460110
      Is it possible to use oxidation numbers?

I was thinking that the stoiciometry might be obtained using the overall reaction. I know that the BDO loses four hydrogen, but I don't think it's all on the form of H+ ions. The reason they didn't post an exact number was that they wanted a general sysnthesis for about a dozen different compunds, but if someone is able an willing to try and balance the equation and figure out the stoichiometry I would really appreaciate that.
C4H8O2C + KMnO4/Al2O3/CuSO4*5H2O -> C4H6O2
Many Thanks,
ShaiGuy

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	All 3 posts		Subject: Stoichiometry Help (BDO->GBL)		Please login to post		Down


		ShaiGuy (Stranger) 09-20-03 07:57 No 460079				Stoichiometry Help (BDO->GBL)
						In the solvent free oxidation of BDO to GBL a 50% potassium permanganate and 50% 20/80 mixture of copper sulphate pentahydrate and alumina are added to BDO at a ratio of 2 mmmol BDO to ~4g oxidant. I'm not sure what the mechanism of this reaction looks like, so I was wondering if anyone could help me figure out a more precise ratio of BDO:oxidant, as I'm not all that confident with "~4g". Many Thanks, ShaiGuy



		Rhodium (Chief Bee) 09-20-03 13:23 No 460097				Stoichiometry
						Maybe the authors of the article wasn't perfectly sure about the mechanism either, and therefore were unable to supply a more precise amount. They may simply have found out by trial and error that this amount gave the best result.



		ShaiGuy (Stranger) 09-20-03 16:40 No 460110				Is it possible to use oxidation numbers?
						I was thinking that the stoiciometry might be obtained using the overall reaction. I know that the BDO loses four hydrogen, but I don't think it's all on the form of H+ ions. The reason they didn't post an exact number was that they wanted a general sysnthesis for about a dozen different compunds, but if someone is able an willing to try and balance the equation and figure out the stoichiometry I would really appreaciate that. C4H8O2C + KMnO4/Al2O3/CuSO4*5H2O -> C4H6O2 Many Thanks, ShaiGuy

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