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All 3 posts | Subject: Grignard Synthesis of Chiral Amphetamines | Please login to post | Down | |||||
Rhodium (Chief Bee) 05-31-04 17:15 No 510550 |
Grignard Synthesis of Chiral Amphetamines (Rated as: good read) |
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Asymmetric α-Substituted Phenethylamines. V. Synthesis of Chiral 1-Alkyl-2-phenylethylamines via Grignard Reaction of 4-Phenyl-1,3-oxazolidines Hiroshi Takahashi,Yasuhiro Chida, Kimio Higashiyama, and Hiraku Onishi Chem. Pharm. Bull. 33(11), 4662-4670 (1985) (https://www.rhodium.ws/pdf/meth.grignard.oxazolidine.pdf) Abstract Chiral N-methyl-4-phenyl-1,3-oxazolidines (2a-e) having a methyl, ethyl, benzyl, isopropyl, and cyclohexyl group at the 2-position of the 1,3-oxazolidine ring were synthesized. Reactions of 2a-e with Grignard reagents gave (1R,1'R)- and (1S,1'R)-1-alkyl- and 1-cycloalkyl-N-2'-hydroxy-1'-phenylethyl-2-phenylethylamines (3a, 3b, 3d, 3e). The absolute configurations of (1R,1'R)-3a and -3e were determined. (R)-1-Methyl- and (R)-1-cyclohexyl-2-phenylethylamines (4a, 4e) were obtained in high yield by hydrogenolysis of (1R,1'R)-3a and -3e. All in all, this reaction may look very complicated, but it really isn't anything else than the procedure in Post 202649 (Rhodium: "Meth via grignard rxn (Gazz Chim Italiana)", Novel Discourse) with the difference being that the aldehyde has been made into an oxazolidine by reaction with a cheap chiral aminoalcohol. The good thing about using this oxazolidine is that 1) The yields are much higher and 2) the result isn't racemic meth, but a single enantiomer. In the article they make l-methamphetamine, but by choosing the other aminoalcohol enantiomer, the reaction will instead produce d-methamphetamine. How do you think this reaction could be streamlined? There is really just a single obstacle in this procedure, and that is the removal of the protection group in the final step, for which they use catalytic hydrogenation. What other aminoalcohols could be used, which would be easier to remove? Could something else be used (which would be a breeze to remove afterwards) if one would be satisfied with racemic product? The Hive - Clandestine Chemists Without Borders |
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Rhodium (Chief Bee) 09-27-04 19:58 No 533428 |
Cathinone from L-PAC (Rated as: good read) |
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Here follows another article on the same topic as the one above (grignard addition to oxazolidines): Untersuchungen zum Konstellationsproblem in der Ephedrinreihe Hermann Pfanz & Gerhard Kirchner Ann. Chem. 614, 149-158 (1958) (https://www.rhodium.ws/pdf/ephedrine.oxazolidines.pdf) The article series below is written by the same author, and contains quite some interesting chemistry: Imidazoline Δ3 I Gerhard Kirchner Ann. Chem. 625, 98-103 (1959) (https://www.rhodium.ws/pdf/ephedrine.imidazoline-1.pdf) ____ ___ __ _ Imidazoline Δ3 II Gerhard Kirchner Ann. Chem. 625, 104-107 (1959) (https://www.rhodium.ws/pdf/ephedrine.imidazoline-2.pdf) ____ ___ __ _ Imidazoline Δ3 III Über intramolekulare Oxydoreduktionen Gerhard Kirchner Ann. Chem. 628, 92-95 (1959) (https://www.rhodium.ws/pdf/ephedrine.imidazoline-3.pdf) The last article contains a synthesis of cathinone from L-PAC by a simple reaction with ammonia and catalytic cyclohexanone: α-Aminopropiophenone (Norephedrone/Cathinone) (-)-Phenylacetylcarbinol [L-PAC] (15 g), cyclohexanone (9.8g)), and 15 mL conc. NH4OH was stirred 5 h, the mixture extracted with ether, the extract dried and distilled to give 10-11g of 3-methyl-2-phenyl-1-oxa-4-aza-spiro[4.5]decane (a.k.a (-)-4-methyl-2,2-pentamethylene-5-phenyl-Δ3-oxazoline, I), bp 120°C/0.3 mmHg, nD20 1.5370, [α]D20 -192.7° (96% EtOH). I (5 g) was heated under reflux for 15 min with anhydrous IPA saturated with HCl, 0.3 ml water was added, and heating continued to give 3.7 g Cathinone·HCl, mp 182°C. The intermediate heterocycle - 3-methyl-2-phenyl-1-oxa-4-aza-spiro[4.5]decane - can also be made from phenylpropanolamine and cyclohexanone by stirring a THF solution of the reactants over 4A Mol sieves for 24h. Ref: Prasad, K. R. K.; Joshi, N. N.; Indian J.Chem.Sect.B 42(1), 150-153 (2003) The Hive - Clandestine Chemists Without Borders |
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Rhodium (Chief Bee) 10-22-04 23:19 No 537215 |
(-)-phenylglycinol -> d-Methamphetamine (Rated as: excellent) |
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The "one-pot" reaction of (-)-phenylglycinol with formaldehyde in the presence of KCN gave the chiral 1,3-oxazolidine (R)-1 as an oil in 94% yield. This synthon was then alkylated twice in the α-position of the cyano group using LDA/MeI followed by LDA/PhCH2Br, the first substitution giving a product with 38% d.e.* and the second >66%. Reduction of the crude product 3 effected decyanation and ring-opening of the oxazolidine to give 4, which in essence is an N-alkylated methamphetamine molecule. If an enantiomerically pure end product is desired, a diastereomer separation is now performed to remove the 15% or so of (R,R)-4 from the remaining 85% of (R,S)-4 through flash chromatography (silica gel, eluting with 5% MeOH in DCM). The unwanted N-alkyl group is then finally removed through overnight hydrogenolysis at atmospherical pressure (MeOH, 10% Pd/C, 12h) to give (S)-N-methyl-α-methyl-phenethylamine 5 (d-Methamphetamine) in 90% yield, with preserved chirality. The overall yield of d-Methamphetamine from the starting R-(-)-phenylglycinol is thus ~20%. *d.e. = Diastereomeric Excess - A measure of diastereomer ratio, defined similarly to enantiomeric excess. (http://www.wiu.edu/users/mftkv/Chem331/enantiomericexcess.html)
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